Solve A+B+B+B+80+90=100 with No negative numbers

Answer: A is log[1/(10^10)] and B is log[1/(10^20)]

Explanation: Mathematical logical Solution: log = -10 log(10) = -10 ->A log = -20 log(10) = -20 ->B Now, So, LHS: A + 3B + 80 + 90 => -10 + 3(-20) + 80 + 90 => 100 -> RHS Hence proved! ( No negative numbers though) Hence, A is log and B is log